∵a+b=0,
∴①当a=0时,b=0,
此时0×x+0=0,
x取任意实数,
②当x≠0时,b=-a,
ax+b=0,即为ax-a=0,
解得x=1,此时方程有唯一解,
综上所述,方程有唯一解或有无数解.
故选C.
If a+b=0,then the equation ax+b=0 for x has( )(英汉小词典:infiniteroots:无穷多个根) A.only one root B.only one root or no root C.
If a+b=0,then the equation ax+b=0 for x has( )(英汉小词典:infiniteroots:无穷多个根)
A. only one root
B. only one root or no root
C. only one root or infinite roots
D. no root or infinite roots
A. only one root
B. only one root or no root
C. only one root or infinite roots
D. no root or infinite roots
其他人气:593 ℃时间:2020-05-14 18:49:36
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