已知X+X的负一次方为负3,求1.X的平方加X的负二平方 2.X的4次方减X的负四

x+1/x=-3
x²+1/x²
=(x+1/x)²-3
=9-2
=7
(x-1/x)²=x²+1/x²-2=7-2=5
x-1/x=±√5
x^4-1/x^4
=(x²+1/x²)(x²-1/x²)
=(x²+1/x²)(x+1/x)(x-1/x)
=7*(-3)*(±√5)
=±21√5