(1)(x2+4x+8)2+3x(x2+4x+8)+2x2
=(x2+4x+8+x)(x2+4x+2x+8)
=(x2+5x+8)(x+2)(x+4);
(2)(2x2-3x+1)2-22x2+33x-1
=(2x2-3x+1)2-11(2x2-3x)-1
=(2x2-3x)2-9(2x2-3x)
=(2x2-3x)(2x2-3x-9)
=x(2x-3)(2x+3)(x-3);
(3)x4+2001x2+2000x+2001
=(x4+x3+x2)-(x3+x2+x)+(2001x2+2001x+2001)
=x2(x2+x+1)-x(x2+x+1)+2001(x2+x+1)
=(x2+x+1)(x2-x+2001);
(4)(6x-1)(2 x-1)(3 x-1)( x-1)+x2
=(6x-1)( x-1)(2 x-1)(3 x-1)+x2
=(6x2-7x+1)(6x2-5x+1)+x2
=(6x2+1-7x)(6x2+1-5x)+x2
=(6x2+1)2-12x(6x2+1)+36x2
=(6x2+1-6x)2;
(5)a2+2b2+3c2+3ab+4ac+5bc
=a2+3ab+4ac+2b2+5bc+3c2
=a2+a(3b+4c)+(2b+3c)(b+c)
=(a+2b+3c)(a+b+c).
分解因式: (1)(x2+4x+8)2+3x(x2+4x+8)+2x2; (2)(2x2-3x+1)2-22x2+33x-1; (3)x4+2001x2+2000x+2001; (4)(6x-1)(2 x-1)(3 x-1)( x-1)+x
分解因式:
(1)(x2+4x+8)2+3x(x2+4x+8)+2x2;
(2)(2x2-3x+1)2-22x2+33x-1;
(3)x4+2001x2+2000x+2001;
(4)(6x-1)(2 x-1)(3 x-1)( x-1)+x2;
(5)a2+2b2+3c2+3ab+4ac+5bc;
(1)(x2+4x+8)2+3x(x2+4x+8)+2x2;
(2)(2x2-3x+1)2-22x2+33x-1;
(3)x4+2001x2+2000x+2001;
(4)(6x-1)(2 x-1)(3 x-1)( x-1)+x2;
(5)a2+2b2+3c2+3ab+4ac+5bc;
数学人气:420 ℃时间:2020-04-20 17:03:35
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