"8V 4W"的电阻器阻值R0=U0^2/P0=8^2/4=16Ω
此电阻电阻为R,则电流I=U/(R+R0)=12/(R+16)
功率P=I^2R=144R/(R+16)^2=2
R^2-40R+16^2=0
R=32Ω,或8Ω
此电阻的阻值是32Ω,或8Ω.
一只电阻与另一只"8V 4W"的电阻器串联在12V的电路中消耗的功率为2W,则此电阻的阻值时多少?
一只电阻与另一只"8V 4W"的电阻器串联在12V的电路中消耗的功率为2W,则此电阻的阻值时多少?
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如题
物理人气:941 ℃时间:2019-10-10 00:59:49
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