已知方程(x-5)/2-a=x-1的解满足不等式组{x/2≤1,x-2≤0,求a的取值范围?
已知方程(x-5)/2-a=x-1的解满足不等式组{x/2≤1,x-2≤0,求a的取值范围?
数学人气：960 ℃时间：2020-04-21 09:41:02
优质解答
(x-5)/2-a=x-1,X=-3-2a,因为x/2≤1,x-2≤0,X≤2 即-3-2a≤2 a大于等于-5/2
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