整理一下,变成(x^2+2x+1)+(4y^2+4y+1)=0
即(x+1)^2+(2y+1)^2=0
由于(x+1)^2≥0,(2y+1)^2≥0
所以(x+1)^2=0,(2y+1)^2=0
x=-1,y=-1/2
x-y=-1/2
x的平方+4乘y的平方+2x+4y+2=0,求x-y的值
x的平方+4乘y的平方+2x+4y+2=0,求x-y的值
数学人气:849 ℃时间:2020-10-01 13:24:51
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