=2
罗比达法则,分子分母求导就得了
求lim(n→0)(e^x-e^-x-2x)/(x-sinx)
求lim(n→0)(e^x-e^-x-2x)/(x-sinx)
数学人气:968 ℃时间:2020-03-29 06:11:24
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