(40×6)÷(40+10)
=240÷50
=4.8(小时)
答:从乙港返回甲港需用4.8小时.
一艘汽船以每小时40千米的速度从甲港开往乙港,需用6小时.返回时,速度每小时提高了10千米,从乙港返回甲港需用几小时?
一艘汽船以每小时40千米的速度从甲港开往乙港,需用6小时.返回时,速度每小时提高了10千米,从乙港返回甲港需用几小时?
数学人气:121 ℃时间:2019-11-13 16:54:15
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