在直角坐标系中,抛物线y=(-4/9)x2+(2/9)mx+(5/9)m+4/3与x轴交与AB两点,点A在负半轴上,点B在正半轴上,且OB=2OA(带绝对值),点C是抛物线的顶点.求m的值.
在直角坐标系中,抛物线y=(-4/9)x2+(2/9)mx+(5/9)m+4/3与x轴交与AB两点,点A在负半轴上,点B在正半轴上,且OB=2OA(带绝对值),点C是抛物线的顶点.求m的值.
数学人气:233 ℃时间:2020-04-15 00:49:04
优质解答
m为4或(-3/2)
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