在三角形abc中,已知内角a=派/3,边bc=2根号下3,设内角b=x,周长为y.

根据正弦定理,b/sinB=a/sinA,a=2√3,
A=π/3,B=x,b=4sinx,c/sinC=a/sinA,
c=2√3/(√3/2)*sinC=4sinC=4sin(A+B)
=4sin(π/3+x)=2√3cosx+2sinx
周长:y=a+b+c=2√3+4sinx+2√3cosx+2sinx
=2√3+6sinx+2√3cosx
0