解方程（x-3)^3+(2x-1)^3+(4-3x)^3=36-12x

令a=x-3,b=2x-1,c=4-3x,则有c=-(a+b)方程化为：a^3+b^3-(a+b)^3=-12a-3ab(a+b)=-12aa=0或b(a+b)=4由a=0得x=3由b(a+b)=4,得：(2x-1)(3x-4)=4,即6x^2-11x=0,得x=0,11/6所以原方程有3个根：x=3,0,11/6...