点A(0,6)和B(0,根号12),
在x轴上有一点p,且△PBA为等腰三角形,则有BP=BA=6-根号12=6-2根号3.
OP^2+OB^2=BP^2
OP^2+12=36+12-24根号3
OP^2=36-24根号3
OP=(+/-)=(+/-)2根号[9-6根号3]
即P坐标是(-2根号(9-6根号3),0)或(2根号(9-6根号3),0)
点A(0,6)和(0,根号12),在x轴上有一点p,且△PBA为等腰三角形,求出p点.
点A(0,6)和(0,根号12),在x轴上有一点p,且△PBA为等腰三角形,求出p点.
数学人气:932 ℃时间:2020-04-17 16:10:38
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