1/(x-2)+k/(x+2)=3/(x²-4)
(x+2)/[(x+2)(x-2)]+k(x-2)/[(x+2)(x-2)]=3/(x²-4)
[kx-2+x+2]/[(x+2)(x-2)]=3/(x²-4)
x(k+1)/(x²-4)=3/(x²-4)
因为方程有增根,所以x=2或-2
当x=2时,2(k+1)=3,解得k=1/2
当x=-2时,-2(k+1)=3,解得k=-5/2
所以k=1/2 或k=-5/2
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关于x的方程1/x-2+k/x+2=3/x^-4有增根,求k的值
关于x的方程1/x-2+k/x+2=3/x^-4有增根,求k的值
数学人气:281 ℃时间:2020-04-03 10:07:17
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