x1²+x2²=(x1+x2)²-2x1x2=m²-(m+2)/2=(m-1/4)²-17/16
m=1/4时,取最小值-17/16
设x1,x2为方程4x²-4mx+m+2=0的两个实根,当m=多少时,x²+x2²有最小值——
设x1,x2为方程4x²-4mx+m+2=0的两个实根,当m=多少时,x²+x2²有最小值——
数学人气:205 ℃时间:2019-08-20 22:11:44
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