原式=-1/(a-2)-[(a+2)/a(a-2)-(a-1)/(a-2)²]×2a/(a-4)
=-1/(a-2)-[(a+2)(a-2)-a(a-1)]/a(a-2)²×2a/(a-4)
=-1/(a-2)-(a²-4-a²+a)/a(a-2)²×2a/(a-4)
=-1/(a-2)-(a-4)/a(a-2)²×2a/(a-4)
=-1/(a-2)-2/(a-2)²
=-(a-2+2)/(a-2)²
=-a/(a-2)²
计算:(1)/(2-a)-((a+2)/(a²-2a)-(a-1)/(a²-4a+4))÷(a-4)/(2a)
计算:(1)/(2-a)-((a+2)/(a²-2a)-(a-1)/(a²-4a+4))÷(a-4)/(2a)
数学人气:272 ℃时间:2019-08-22 11:33:53
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