化简代数式x2−1x2+2x÷x−1x，并判断当x满足不等式组x+2＜12(x−1)＞−6时该代数式的符号．

x2−1x2+2x÷x−1x=x2−1x2+2x•xx−1=(x −1)(x+1)x(x +2)•xx−1=x+1x+2，不等式组x+2＜1①2(x−1)＞−6②，解不等式①，得x＜-1．解不等式②，得x＞-2．∴不等式组x+2＜12(x−1)＞−6的解集是-2＜x＜-1...