要求 |

a^5=b^4(b/a)^4=a令b/a=x,则a=x^4c^3=d^2(d/c)^2=c令d/c=yc=y^2a-c=19所以x^4-y^2=(x^2+y)(x^2-y)=19=19*1y>0,所以x^2+y>x^2-y所以x^2+y=19x^2-y=1所以x^2=10,y=9应该是求d-b吧?a=x^4,a^5=b^4所以x^20=b^4所以b=x^5...