原式=(3a²+ab-9ab-3b²)-(a²-25b²)=3a²-8ab-3b²-a²+25b²=2a²-8ab+22b²=2*(-8)²-8*(-8)*(-6)+22*(-6)²=536先化简，再求值：（a-3b)(3a+b)-(a+5b)(a-5b),其中a=-8,b=-6
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先化简,再求值：（a-3b)(3a+b)-(a+5b)(a-5b),其中a=-8,b=-6
先化简,再求值：（a-3b)(3a+b)-(a+5b)(a-5b),其中a=-8,b=-6
数学人气：183 ℃时间：2020-04-11 03:58:56
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