设向量c=m向量a+n向量b.
∵向量a=2e1-e2,b=-e1+e2,c=e1-e2
∴向量c=m(2e1-e2)+n(-e1+e2)=(2m-n)e1+(n-m)e2
又∵向量e1、e2不共线
∴2m-n=1①,n-m=-1②
联立①、②解得m=0,n=-1
∴答:向量c=-b.
设向量e1、e2不共线,a=2e1-e2,b=-e1+e2,c=e1-e2,试用向量a、b为基底来表示向量c.
设向量e1、e2不共线,a=2e1-e2,b=-e1+e2,c=e1-e2,试用向量a、b为基底来表示向量c.
数学人气:860 ℃时间:2020-04-04 22:26:40
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