f(x)=2x+1/x+1=(2(x+1)-1)/(x+1)=2-1/(x+1)
1<=x<=4
2<=x+1)<=5
所以,1/5<=1/(x+1)<=1/2
-1/2<=-1/(x+1)<=-1/5
3/2<=2-1/(x+1)<=9/5
即最大值是9/5,最小值是3/2
求函数f(x)=2x+1/x+1在区间[1,4]上的最大值最小值
求函数f(x)=2x+1/x+1在区间[1,4]上的最大值最小值
数学人气:798 ℃时间:2019-08-17 01:19:04
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