题目不全,
当x=3时,多项式ax^5+bx^3+cx-10的值为7,则当x=-3时,这个多项式的值是多少?
x=3时,
ax^5+bx^3+cx-10=7
ax^5+bx^3+cx=17
x=-3时
a(-x)^5+b(-x)^3+c(-x)-10
=-(ax^5+bx^3+cx)-10
=-17-10
=-27
当x=-3时,多项式ax^5+bx^3+cx-10的值是
当x=-3时,多项式ax^5+bx^3+cx-10的值是
数学人气:759 ℃时间:2019-09-21 06:44:02
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