AB直线方程y=x+1;
点C(3,5)不满足AB的直线方程,故C不在AB所在的直线上,
所以ABC三点不共线
已知三点A(0,1),B(2,3),C(3,5) ,求证:ABC三点共线
已知三点A(0,1),B(2,3),C(3,5) ,求证:ABC三点共线
数学人气:728 ℃时间:2020-04-05 06:50:04
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