二次函数顶点公式以及对称轴公式-b/2a,4ac-b^2/4a推导的2过程-b/2a,4ac-b^2/4a

配方 y=ax^2+bx+c =a(x^2+bx/a)+c =a[x^2+2*(b/2a)*x+(b/2a)^2-(b/2a)^2]+c =a(x+b/2a)^2-a*b^2/4a^2+c =a(x+b/2a)^2-b^2/4a+4ac/4a =a(x+b/2a)^2+(4ac-b^2)/(4a) =a[x-(-b/2a)]^2+(4ac-b^2)/(4a) 所以顶点是[-b/2a,...