(x-3)(2x+2)=0
9(x-1)²-4(x-5)²=0 (9x-9+2x-10)(9x-9-2x+10)=0 (11X-19)(7X+1)=0
X²-5X+6-2=0 ( X-1)(X-4)=0 X=1,X=4第一个是用的提取公因式法么?还有第二个已经是最简方法吗?可是按照答案来说第二个你给的好像算出来的不对啊!你写(11x-19)(7x+1)=0 那x1=19\11,x2=-7\1,可是答案是五分之十三和-7啊!(3x-3+2x-10)(3x-3+2x-10)=0因式分解啊,a²-b²=(a+b ) x(a-b)
选择适当的方法解下列一元二次方程
选择适当的方法解下列一元二次方程
1.2x²-4x-6=0
2.9(x-1)²=4(x-5)²
3.(x-3)(x-2)=2
1.2x²-4x-6=0
2.9(x-1)²=4(x-5)²
3.(x-3)(x-2)=2
数学人气:240 ℃时间:2020-06-14 23:20:38
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