1kw·h=3600000J
由w=pt得t=w/p=3600000J/500W=7200s
7200s=2h
1kw·h=3600000J
由w=pt得t=w/p=3600000J/100W=36000s
36000s=10h
一个500W的电烤箱工作多少小时消耗1度电,1度电可供100W的灯工作多少小时
一个500W的电烤箱工作多少小时消耗1度电,1度电可供100W的灯工作多少小时
其他人气:869 ℃时间:2019-10-18 02:35:18
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