1/2*[1/x-1/(x+2)+1/(x+2)-1/(x+4)......+1/(x+28)-1/(x+30)]
=1/2*[1/x-1/(x+30)]
计算:1/X(X+2)+1/(X+2)(X+4)+...+1/(X+28)(X+30)
计算:1/X(X+2)+1/(X+2)(X+4)+...+1/(X+28)(X+30)
数学人气:599 ℃时间:2020-06-15 14:59:59
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