已知(sin^2a+4)/(cosa+1)=2 那么(cosa+3)(sina+1)值为多少
已知(sin^2a+4)/(cosa+1)=2 那么(cosa+3)(sina+1)值为多少
数学人气:936 ℃时间:2020-01-04 23:35:23
优质解答
(sin^2a+4)/(cosa+1)=2即sin^2a+4=2cosa+2sin^2a-2cosa+2=0sina转化为cosa得:3-2cosa-cos^2a=0(3+cosa)(1-cosa)=0由于cosa的值域为(-1,1)所以1-cosa=0即cosa=1sina=0(cosa+3)(sina+1)=(1+3)*(0+1)=4...
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