求函数y=2x-3-根号下13-4x的值域

设根号下13-4x=t,则t≥0则t^2=13-4x,x=(13-t^2)/4则y=(13-t^2)/2-3-t=-(t^2)/2-t+7/2=-1/2[t^2+2t]+7/2=-1/2[(t+1)^2-1]+7/2=-1/2(t+1)^2+4因为t≥0,y=f(t)图象为开口向下,顶点为(-1,4)的抛物线所以f(t)max=f(0)=7/2...