2sin(2x+π/4)>-√2
sin(2x+π/4)>-√2/2
2kπ2sin(2x+π/4)+√2>0sin(2x+π/4)>-√2/22kπ-π/4<2x+π/4<2kπ+5π/42kπ-π/2<2x<2kπ+6π/4kπ-π/4
若函数y=log1/2[2sin(2x+π/4)+√2]的定义域
若函数y=log1/2[2sin(2x+π/4)+√2]的定义域
数学人气：782 ℃时间：2020-04-19 22:05:24
优质解答
2sin(2x+π/4)+√2>0
2sin(2x+π/4)>-√2
sin(2x+π/4)>-√2/2
2kπ2sin(2x+π/4)+√2>0sin(2x+π/4)>-√2/22kπ-π/4<2x+π/4<2kπ+5π/42kπ-π/2<2x<2kπ+6π/4kπ-π/402sin(2x+π/4)>-√2sin(2x+π/4)>-√2/22kπ-π/4<2x+π/4<2kπ+5π/42kπ-π/2<2x<(2k+1)πkπ-π/4
2sin(2x+π/4)>-√2
sin(2x+π/4)>-√2/2
2kπ2sin(2x+π/4)+√2>0sin(2x+π/4)>-√2/22kπ-π/4<2x+π/4<2kπ+5π/42kπ-π/2<2x<2kπ+6π/4kπ-π/4
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