设一次函数f（x）=AX+B
则有 F(X+1)-2F(X-1)=A(X+1)+B-2(A(X-1)+B)
=-AX+3A-B=5X+1
等式恒等
必然 -A=5 3A-B=1
==>A=-5,B=-16
所以F(X)=-5X-16
一次函数f（x）满足f（x+1）-2f（x-1）=5x+1
一次函数f（x）满足f（x+1）-2f（x-1）=5x+1
数学人气：496 ℃时间：2020-03-29 03:16:54
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