∠60°,那一角?
BM=2AM
BA+AM=2AM
BA=AM
c^2 = a^2+b^2-2abcosC
= 1+4-2(1)(2)cos60°
= 3
c =√3
by sine rule
a/sinA = c/sinC
1/sinA = √3/sin60°
sinA = 1/2
A = 30°
cosA = √3/2
CM.CA
= (CA+AM).CA
=(CA+BA).CA
=|CA|^2 + |BA||CA|cosA
= b^2+bccosA
=4+2(√3)(√3/2)
=4+3
=7
ΔABC中,∠60°,且CA=2,CB=1,点M满足向量BM=2AM,则向量CM*CA=
ΔABC中,∠60°,且CA=2,CB=1,点M满足向量BM=2AM,则向量CM*CA=
数学人气:145 ℃时间:2019-10-17 06:05:46
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