(2x-1)/3-(10x+1)/12=(2x+3)/4-1

(2x-1)/3-(10x+1)/12=(2x+3)/4-1
两边同时乘以12,得
4(2x-1)-(10x+1)=3(2x+3)-12
8x-4-10x-10=6x+9-12
-2x-14=6x-3
-8x=11
x=-11/84x/1.2-0.84x-1/0.24=3/2[2/3(x/4-1)-2]-x4x/1.2-(0.84x-1)/0.24=3/2[2/3(x/4-1)-2]-x4x/(6/5)-(21/25x-1)/(6/25)=3/2(x/6-2/3-2)-x10/3x-21/25×25/6x+25/6=x/4-1-3-x10/3x-21/6x+25/6=-3/4x-4两边同时乘以12，得40x-42x+50=-9x-48-2x+50=-9x-487x=-98x=-14