已知abc=1,求a/ab+a+1 + b/bc+b+1 + c/ca+c+1的值
已知abc=1,求a/ab+a+1 + b/bc+b+1 + c/ca+c+1的值
其中
x=根号下19-8倍根号3
=根号下[4^2+(根号3)^2-2*4*根号3]
=根号(4-根号3)^2
=4-根号3
x-4=-根号3
(x-4)^2=3
x^2-8x+13=0
x^2-8x+13=0,
所以x^2-8x+15=2;
x^4-6x^3-2x^2+18x+23
=x^2(x^2-8x+13)+2x^3-15x^2+18x+23
=2x(x^2-8x+13)+x^2-8x+23
=x^2-8x+23
=x^2-8x+13+10=10
所以:(x^4-6x^3-2x^2+18x+23)/(x^2-8x+15)=10/2=5
=2x(x^2-8x+13)+x^2-8x+23是如何得到的 仅此而已 但愿不要废话
其中
x=根号下19-8倍根号3
=根号下[4^2+(根号3)^2-2*4*根号3]
=根号(4-根号3)^2
=4-根号3
x-4=-根号3
(x-4)^2=3
x^2-8x+13=0
x^2-8x+13=0,
所以x^2-8x+15=2;
x^4-6x^3-2x^2+18x+23
=x^2(x^2-8x+13)+2x^3-15x^2+18x+23
=2x(x^2-8x+13)+x^2-8x+23
=x^2-8x+23
=x^2-8x+13+10=10
所以:(x^4-6x^3-2x^2+18x+23)/(x^2-8x+15)=10/2=5
=2x(x^2-8x+13)+x^2-8x+23是如何得到的 仅此而已 但愿不要废话
数学人气:291 ℃时间:2019-10-23 10:43:13
优质解答
上一个式子=2X ( x * 2- 8X+ 13) + 2x + 2*2 x -30 x+18 x + 23,那么2* 2x - 30x + 18x 就等于- 8x
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