延长CE与AD的延长线与M则△ACEr≌△AEM
CE=EM1/2CM
∠FAD+∠M=90°
∠DcM +∠M =90°
∠FAD =∠DCM
∠ADC =∠CDM =90°
AD=DC
△ADF≌△CDM
AF =CM
CE =1/2AF
已知正方形ABCD中,CE垂直于∠CAD平分线于E,AE交DC于F,求证：CE=1/2AF
已知正方形ABCD中,CE垂直于∠CAD平分线于E,AE交DC于F,求证：CE=1/2AF
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数学人气：875 ℃时间：2020-04-22 15:13:59
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