Y=根号下3+2x-x²求值域.
Y=根号下3+2x-x²求值域.
数学人气:668 ℃时间:2020-04-05 12:04:20
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Y=根号下3+2x-x²3+2x-x²≥0;x²-2x-3≤0;(x-3)(x+1)≤0;-1≤x≤3;y=√-(x-1)²+4;x=1时;最大值=2;x=3或-1时;最小值=0;值域为[0,2]很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么不...
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