∫[(1-x)/(1+x^2)]dx
=∫1/(1+x^2)dx-∫x/(1+x^2)dx
=arctan x-1/2*ln(1+x^2)+C
请问如何解此不定积分[1-x/(1+x^2)]dx
请问如何解此不定积分[1-x/(1+x^2)]dx
要具体的步骤,一定要具体清晰的,
应该是这样的,没写清[(1-x)/(1+x^2)]dx
要具体的步骤,一定要具体清晰的,
应该是这样的,没写清[(1-x)/(1+x^2)]dx
数学人气:509 ℃时间:2020-04-13 11:55:45
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