a的n-5次方×(a的n+1次方b的3m-2次方)的二次方×(-b的3m+2次方)+a的n-1次方

a^(n-5)×[a^(n+1)b^(3m-2)]²×[-b^(3m+2)]+[a^(n-1)*b^(m-2)]³ [-b^(3m+2)]=-a^(n-5)×a^2(n+1)b^2(3m-2)×b^(3m+2)-a^3(n-1)*b^3(m-2)b^(3m+2)=-a^(3n-3)b^(9m-2)×-a^(3n-3)*b^(9m-4)和阁下的答案不一...