分式的乘除（两题都要有步骤）1、(a的n+1次方c的n次方/b的n-1次方)的平方

解1题：原式=(a的n+1次方c的n次方)²/(b的n-1次方)²=[a的2(n+1)次方c的2n次方]/[b的2(n-1)次方]=(a的2n+2次方c的2n次方)/(b的2n-2次方)解2题：原式=[(b^3n-1)/(a^2n+1)]×c÷[(b^3n-2)/(a^2n)]=[(b^3n-1)/(...