如图,质量m为2kg的物体,与天花板成53°角的力F作用下,沿着天花板从静止开始做匀加速直线运动,运动5m后,

F 分解为垂直于天花板的 F1 = Fsin(53°) = 50 * 0.8 = 40 [N]
F2 = Fcos(53°) = 50 * 0.6 = 30 [N]
2as = v(t)^2 - v0^2
a = 100/(2*5) = 10 [m/s^2]
F2 - f = 20 [N]
f = 10 [N]
N = F1 - mg = 40 - 20 = 20
μ = 0.5