因为A是B的真子集,
所以可将A中元素1代入集合B,
得:1²-3+a=0
所以:a=2
已知集合A={1},集合B={x|x^-3x+a=0},且A是B的真子集,求实数a的值.
已知集合A={1},集合B={x|x^-3x+a=0},且A是B的真子集,求实数a的值.
只需说明原因就可
只需说明原因就可
数学人气:251 ℃时间:2020-03-17 07:39:30
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