如图,已知AB,AC为弦,OM⊥AB于点M,ON⊥AC于N,BC=4,求MN的长.

设OB=OA=OC=r,∠BOA=2b,∠COA=2c,则BC^2=2r^2[1-cos(2b+2c)]=4r^2sin^2(b+c),sin(b+c)=2/rOM=rcosb,ON=rcoscMN^2=OM^2+ON^2-2*OM*ON*cos(b+c)=r^2(cos^2b+cos^2c)-2r^2cosbcosccos(b+c)还需要知道AB、AC的比例关系...