x﹙x+1﹚-﹙x2+y﹚=﹣1
x²+x-x²-y=-1
x-y=-1
所以原式=(x²+y²-2xy)/2
=(x-y)²/2
=1/2x(x+1)-(x²+y)=-1,则(x²+y²)÷2-xy=( )做了,采纳吧
已知x﹙x+1﹚-﹙x2+y﹚=﹣1,则x2+y2/2-xy=﹙ ﹚
已知x﹙x+1﹚-﹙x2+y﹚=﹣1,则x2+y2/2-xy=﹙ ﹚
x(x+1)-(x²+y)=-1,则(x²+y²)÷2-xy
x(x+1)-(x²+y)=-1,则(x²+y²)÷2-xy
数学人气:547 ℃时间:2020-03-25 13:45:30
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