f(x)=2cos(x+π/3)[sin(x+π/3)-√3cos(x+π/3)]
=4cos(x+π/3)[1/2sin(x+π/3)-√3/2cos(x+π/3)]
=4cos(x+π/3)[sin(x+π/3-π/3)]
=4[cosxcos(π/3)-sinxsin(π/3)]*sinx
=2(cosx-√3sinx)sinx
=2cosxsinx-2√3sin²x
=sin2x+√3cos2x-√3
=2sin(2x+π/3)-√3,在[0,π/6]上,f(x)∈[1-√3,2-√3]
m[f(x)+√3]+2=0恒成立,即[f(x)+√3]=-2/m恒成立,所以1
已知函数f(x)=2cos(x+π/3)[sin(x+π/3)-√3cos(x+π/3)]
已知函数f(x)=2cos(x+π/3)[sin(x+π/3)-√3cos(x+π/3)]
对任意x属于[0,π/6],使得m[f(x)+√3]+2=0恒成立,求实数m的取值范围.
对任意x属于[0,π/6],使得m[f(x)+√3]+2=0恒成立,求实数m的取值范围.
数学人气:991 ℃时间:2019-11-02 21:37:54
优质解答
我来回答
类似推荐
- 已知函数f(x)=2cos(x+三分之派)【sin(x+三分之派)-根号3cos(x+三分之派)】,求函数的最小正周期和单调递减区间
- 已知函数f(x)=sin(x+π/4)+2cos(x-π/4)+2sin2x+3cos(x+3π/4) ; g(x)=f(x)+f^2(x/2)
- 设函数f(x)=根号3cos^2cos+sinωrcosωx+a(其中ω>0,a∈R),且f(x)的图像在y轴右侧的第一个高点的横坐标为x/6.(1)求ω的值(2)如果f(x)在区间[-π/3,5π/6]上的最小值为根号3,求a的值
- 设函数f(x)=sin(πx/4-π/6)-2cos^2πx/8+1
- 一,设函数f(x)=sin(πx/3-π/6)-2cos^2πx/6.
猜你喜欢
- 1Travelling has been popular with people for a long time.Many of today's travellers are trying to find an unusual experie
- 2英语翻译
- 3三个人坐五个椅子,
- 4Not only do I feel good about helping other people中的do什么意思?为什么要用它?
- 5加工一批零件,已完成个数与零件总个数的比是1:3.如果再加工15个,那么完成个数与剩下的个数同样多,这批
- 6小学英语连词成句练习题
- 7已知数字5的ASCII码的十进制值是53,9的ASCII十六进制值是多少
- 8介词填空:I always eat my breakfast ---------- going to school---------- the morning.
- 9元宵节的习俗(用英语)
- 10把13分之7化成小数后,小数部分的前2009位数字和是多少,怎么求