(3x-2）平方=9x

(3x-2）^2=9x
9x^2-12x+4=9x
9x^2-21x+4=0
x=[21±√(441-144)]/18
=[7±√33]/6
配方：
(3x-2）^2=9x
9x^2-12x+4=9x
9x^2-21x+4=0
9(x^2-7x/3)+4=0
9(x-7/6)^2+4-49/4=0
9(x-7/6)^2=33/4
(x-7/6)^2=33/36
所以 x=[7±√33]/6