[sin(540-a)*cot(-a-270)*cos(360-a)] / [tan(a-180)*tan(a+450)*sin(360-a)]
=[sin(180-a)*cot(90-a)*cosa]/[tana*tan(a+90)*sin(-a)]
=[sina*tan(-a)*cosa]/[tana*cota*(-sina)]
=[-sina*tana*cosa]/[-tana*cota*sina]
=cosa/cota
=sina
[sin(540-a)*cot(-a-270)*cos(360-a)] / [tan(a-180)*tan(a+450)*sin(360-a)]
[sin(540-a)*cot(-a-270)*cos(360-a)] / [tan(a-180)*tan(a+450)*sin(360-a)]
化简,会的写下过程,对的立即采纳
到底谁对啊?有个明确的答案
化简,会的写下过程,对的立即采纳
到底谁对啊?有个明确的答案
数学人气:663 ℃时间:2019-10-09 12:18:55
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