如果(x+3/2)-(x-8/6)与1-(2x+1/3)互为相反数,求方程ax-3=a+x中a的值

啊,刚才算错了
即(x+3/2)-(x-8/6)+1-(2x+1/3)=0
3/2+8/6+1-2x-1/3=0
9/6+8/6+6/6-2/6=2x
21/6=2x
x=7/4
ax-3=a+x
a(x-1)=x+3
a=(x+3)/(x-1)=57/9=19/3能不能这样：(X+3)/2-(X-8)/6=-(1+[2X+1/3])??是(x+3/2)还是(x+3)/2?我上面是按(x+3)/2算的是2X+1/3还是(2x+1)/3?是(2x+1)/3(X+3)/2-(X-8)/6=-(1-(2X+1)/3)，两边同时乘以63(x+3)-(x-8)=-(6-2(2x+1))3x+9-x+8=-6+4x+221=2xx=21/2ax-3=a+xa(x-1)=x+3a=(x+3)/(x-1)=27/19