(2x+3)^2=(5x-4)^2
方法一:2x+3=5x-4 得:x=7/3
或:2x+3=-5x+4 得:x=1/7
方法二:
(2x+3)^2=(5x-4)^2
(2x+3)^2-(5x-4)^2=0
(2x+3+5x-4)(2x+3-5x+4)=0
(7x-1)(7-3x)=0
x=1/7 或 x=7/3
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