令cosa=√5/5,sina=2√5/5
y=sin(3x+π/4)+2cos(3x+π/4)
=√5[√5/5sin(3x+π/4)+2√5/5cos(3x+π/4)]
=√5[√5/5sin(3x+π/4)+2√5/5cos(3x+π/4)]
=√5[sin(3x+π/4)cosa+cos(3x+π/4)sina]
=√5sin(3x+π/4+a)
T=2π/3
函数y=sin(3x+π/4)+2cos(3x+π/4)的最小正周期是
函数y=sin(3x+π/4)+2cos(3x+π/4)的最小正周期是
数学人气：183 ℃时间：2020-03-23 13:05:04
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