已知a为第二象限角,且|a+2|
已知a为第二象限角,且|a+2|<=4,则a的范围
|a+2|<=4
-4<=a+2<=4
-6<=a<=2
a为第二象限角
2kπ+π/2
|a+2|<=4
-4<=a+2<=4
-6<=a<=2
a为第二象限角
2kπ+π/2
数学人气：924 ℃时间：2020-03-19 04:36:51
优质解答
2kπ+π/2
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