a²-10a+25+b²-8b+16=0
(a-5)²+(b-4)²=0
a=5,b=4
(5-4)
已知a,b,c是△ABC的三边长,且满足a²+b²-10a-8b+41=0,求c的取值范围.
已知a,b,c是△ABC的三边长,且满足a²+b²-10a-8b+41=0,求c的取值范围.
数学人气：326 ℃时间：2020-03-24 23:43:31
优质解答
a²+b²-10a-8b+41=0
a²-10a+25+b²-8b+16=0
(a-5)²+(b-4)²=0
a=5,b=4
(5-4)
a²-10a+25+b²-8b+16=0
(a-5)²+(b-4)²=0
a=5,b=4
(5-4)
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